Similar Posts

Subscribe
Notify of
2 Answers
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
Willy1729
10 months ago

Hello,

Tasks a and b were correct.

At c, it does not even mean everything except once and not at all.

So you have to calculate the likelihood that the event arrives exactly once and that the result is 1 .

For task d, you have to go over the counter probability.

In order to arrive at least once at 95 % event B, the probability that it does not arrive at all must fall to 5 % or less.

You are counting (19/27)^n≤=0.05.

Task e is correct.

For task f you count (8/27+1/27)^5. This is the probability for five times consecutive B or 2xx2.

Expected value for B at 100 games is about 30. It is unusual that only deviations were observed downward, but not upward.

Maybe something is wrong with the device.

Best regards,

Willy