Speed of car in position B?
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If no frictional force acts, the sum of potential and kinetic energy remains constant along the path. So it applies
hA and hB are given or can be calculated easily. vA=0, since the car is in rest at A. Thus vB remains the only unknown after which it can be dissolved.
Short version: the kinetic energy in B corresponds to the decrease in potential energy m*g*(hA-hB).
PS: I see that you have posted the same task a few minutes ago.
That's easy!
Energy conservation rate.
in A the car has location energy
in B, it has some position energy (h=5 m) and a lot of motion energy that is as large as it has lost in position energy (calculate difference height).