Series connection or parallel connection – calculation?

Good bye,

I am currently calculating this circuit.

I would like to calculate Rges, but I'm not sure which approach would be correct because I don't have a solution and google gemini shows me a different solution.

My calculation:
1. R1+R2+R3 = 3 + 3 + 4 = 10 ohms

2. R123||R4 = ((10*20)/(10+20)) = 20/3 ohms (6.67 ohms)

3. R1234 || R5 = ((20/3 * 10) / (20/3+10)) = 4 ohms

Thus Rges = 4 Ohm

Google Gemini

1. R1+R2+R3 = 3 + 3 + 4 = 10 ohms

2. R123||R4 = ((10*20)/(10+20)) = 20/3 ohms (6.67 ohms)

3. R1234 + R5 = 10 ohms + 6.67 ohms = 16.67 ohms

Thus Rges = 16.67 Ohm

The difference lies in the last point. Now to my question: is the last one really connected in series?

(1 votes)
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AMG38
1 year ago

Gemini calculated the resistance of the circuit. That’s what you think of the open terminals A and B, because they hang in the air. Then R5 is in series with the remaining replacement resistor R1234.

On the other hand, you have determined the resistance from the point of view of the terminals A and B, then R5 is parallel to the remaining spare resistance R1234.

As mentioned, here is of concern, WAS you mean with Rges.

I didn’t count the values.

isohypse
1 year ago

4 Ohm as Internal resistance of the replacement source between AB It’s okay.

That it can’t be 16 ohms is clear.

But you should have said what you want to calculate and what you mean with Rges…

isohypse
1 year ago
Reply to  cool27

Calculate currents I1, I4 and I5 using the superposition set

is an understandable task

“Calculate all resistors to a large resistor

is reckless if there is no further indication. Don’t think it’s like that.

W18J66
1 year ago

The sum rule that means that the sum of all voltages (also voltage drops) in the circuit is=0. Watch the polarities!