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Yeah, that’s right. In this case, the coin is not yet in motion at an angle of 25°, so only the static friction acts. The sliding friction occurs only when the coin begins to slide, i.e. at an angle of 35°.
The static friction force is therefore equal to the slope output force, multiplied by the static friction coefficient:
F_H = mg sin α = μ_H mg cos α
μ_H = tan α = tan 25° = 0.466
The sliding friction force, on the other hand, is equal to the slope output force, multiplied by the sliding friction coefficient:
F_G = mg sin α = μ_G mg cos α
μ_G = tan 35° = 0,70
The value of μ_H is therefore correct in the illustration.
in the solution it has been made differently, the angle interchanged.