ByGorumate
Good day,
I'm stuck. I just tried to solve the redox reaction, but I'm not getting anywhere.
The following scenario: Step 2: Synthesis of propanoic acid from propan-1-ol with Cr2O72- in acidic solution. Propan-1-ol is mixed with an acidic dichromate solution. This creates a thorough solution of Cr3+ ions and the organic acid, which is separated from the mixture.
Set the second synthesis step the complete reaction equation
Thank you in advance
(1 votes)
Loading...in question 4 after adding 10ml of sodium hydroxide solution?
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This is part 1. How do I illustrate this?
Hi guys, Can someone maybe help me with these two tasks?
The oxidation numbers of the functionalized carbon are CH3–CH2–C ̄IH2OH and CH3–CH2–C+IIIO–OH. The oxidation reaction thus releases four electrons. Six electrons are reacted in the reaction:
CH3–CH2–C ̄IH2OH
Cr+VI2O72 ̄ + 6 e ̄ ⟶ 2 Cr3+
We could balance this, but I’ll move it to later. Instead, we add three times the oxidation reaction to double the reduction reaction, then the 12 e ̄ away, and we get
2 Cr2O72 ̄ + 3 CH3CH2CH2OH ⟶ 4 Cr3+ + 3 CH3CH2COOH
In this case, the chromium and carbon balances are automatically already correct, because they were already balanced in the partial reactions. The other little one will have to and will still care. On the left we have −4 loads and on the right +12, so on the left we can add 16 H3O+, then the cargo balance is correct.
2 Cr2O72 ̄ + 3 CH3CH2CH2OH + 16 H3O+ ⟶ 4 Cr3+ + 3 CH3CH2COOH
Now we have 33 O atoms left, but only six on the right. So we write 27 H2O to the right
2 Cr2O72 ̄ + 3 CH3CH2CH2OH + 16 H3O+ ⟶ 4 Cr3+ + 3 CH3CH2COOH + 27 H2O
Since we have nothing more to compensate, the hydrogen balance should be correct by itself, and that is it (left and right each 72). So the equation is true.
P.S.: Reading error during the first attempt of an answer.
I’ll take a look or I’d be happy if you could answer questions again.
Thanks for the detailed answer
The bill of propan-1-ol is understandable, except why we have -1 for carbon?
The explanation was mega long ago that we made Redox. Thank you again. :)))
Type the structural formula: The carbon has
So in this count we have 5 electrons for the carbon atom. In the element, it has four valence electrons, in the propanol of a more, i.e. oxidation number −I. The same computation procedure results −III in the propanoic acid, because the C only gets one electron (one from the C—C bond), i.e. has three electrons less than in the element.