Pythagorean theorem?
Why doesn't the problem use 191.69? Why does it use 128 + 64?
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Or cuboid – half cylinder I would have done it like this: AoQ-(6×5)-AGHZ+AMHZ
I think it was just rounded because you were “too lazy” to continue with the comma.
But it would of course be more correct to expect from 191,69.
And I assume that no one can count the root of 192 in the head. If you type it into the calculator anyway, you could actually count exactly.
Above all, it doesn’t make sense to keep the two descendants in the final result.
it was rounded. But why? Do you have to ask the manufacturer of the lines or the identical teaching power
also root 192 can only be calculated with the TR, since you can also enter 191.69
In addition, d is 13.84, which is already a difference
However, one can stand on the point of view as a teacher: It’s only about principle, so you don’t need THE normal accuracy
There’s someone inconsistent. If he calculates in between without decimal places, it makes no sense to indicate decimal places as a result.
Then it was rounded too early, d = 13.85 cm (rounded to 2 places).
Because 11.32 = 127.69 is, and this is about 128.
But this is very generously rounded. You don’t normally.
The only reason I think is that the FS is still in a lower class and is therefore rounded to whole numbers for simplicity.
I find the rounding in place also unusual. Maybe just a whim of the teacher?
In the lower school levels, it is also possible to take tasks where there are “beautiful” results.
It was said that it should make a difference, but what seems strange to me.
I didn’t make the sample solution.