Prove that product quantities are equal?

Hello,

to show the equality of the following sets:



First, I interpreted the quantities on either side of the equation as M and N. Therefore, for the two quantities to be equal, the following must hold:



I then assumed that the tuple T was an element of the set M (in this case, the set on the left in the equation). This yields:



For the elements x and y of the tuple T we get:



At this point it becomes clear to me that x and y can both exist in only one of the two combined sets in order for the equation to be satisfiable under the previously made assumption. If x is an element of A , then it must not also be an element of C. In addition, in this case y must be an element of D , but not of B. If x is an element of C and not of A , then y must be an element of B , but not of C. These two possible cases are logically expressed by the right-hand side of the equation.

I hope you understand my train of thought. However, I'm having a little trouble mathematically proving what I described above.

I look forward to your advice and please correct me if I misunderstood something!

(2 votes)
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LUKEars
5 months ago

so to the left of the equal sign is:

Now you could make a truth table… or apply some other calculation rules that I can't think of right now…

 xA xC yB yD | LHS RHS 0 0 0 0 | 0 0 0 0 1 | 0 0 0 1 0 | 0 0 0 1 1 | 0 0 1 0 0 | 0 0 1 0 1 | 1 0 1 1 0 | 1 0 1 1 1 | 0 1 0 0 0 | 0 1 0 0 1 | 1 1 0 1 0 | 1 1 0 1 1 | 0 1 1 0 0 | 0 1 1 0 1 | 0 1 1 1 0 | 0 1 1 1 1 | 0

the same for the right side…

or?

LUKEars
5 months ago
Reply to  Kattalysator

dange für den Stern… *hüpf* 🫡

MagicalGrill
5 months ago

If x is an element of A, y must not be an element of B (otherwise (x,y) would be an element of A x B).

This means that y is automatically an element of D (it must lie in the union B and D).

This means that x is not an element of C (otherwise (x,y) would be an element of C x D).

LUKEars
5 months ago
Reply to  MagicalGrill

Couldn't x be from C and y from either B or D? So, a kind of XOR?

MagicalGrill
5 months ago
Reply to  LUKEars

What I wrote above applies if x is from A. Of course, in general, x is only from the union of A and C, which means that one must also consider the case where x is not from A. The argument can be made analogously:

Then x is in C (it must lie in the union A and C).

Then y must not be an element of D (otherwise (x,y) would be an element of C x D).

This means that y must be an element of B (it must lie in the union B and D).

Thus (x, y) is an element of (C \ A) x (B \ D).