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Willy1729
1 year ago

Hello,

first two branches for the length with stock and faulty.

If 4% are faulty, 96% are without fault.

Two of these two branches go away again.

This time, 9% are faulty and thus 91% are error-free.

Best regards,

Willy

Willy1729
1 year ago
Reply to  Usernotfound01

At b you calculate length consisted times diameter=0.96*0.91=0.8736 0der 87.36%.

At c you calculate length consisted times diameter faulty plus length faulty times diameter consisted equal
0.96*0.09+0.91*0.04=0.1228 or 12.28%.

Wechselfreund
1 year ago
Reply to  Willy1729

In the second stage, one can really assume 0.09 and 0.91 with jde path pair. Or did I get you wrong?

Willy1729
1 year ago
Reply to  Wechselfreund

Sura. These data refer to all waves, whether their lengths are faulty or not. The errors in length and diameter are independent of one another.

Willy1729
1 year ago

There is no indication of a relationship between faulty length and faulty diameter. That would have to be mentioned otherwise.

Wechselfreund
1 year ago

I wasn't sure. I looked at this after a conditional probability.