pq formula coefficient of 2 to 1?
I have the term 2x^2-x-3 and want to apply pq formula so I halve everything
then have x^2-0.5x-1.5
Then why do the zeros always change when it becomes 1x^n?
For example, if I have 4x^2-2x-6, are the zeros identical?
I have the term 2x^2-x-3 and want to apply pq formula so I halve everything
then have x^2-0.5x-1.5
Then why do the zeros always change when it becomes 1x^n?
For example, if I have 4x^2-2x-6, are the zeros identical?
Are there any problems with an infinitely large resistance from an electrical engineering point of view, for example if the capacitance becomes small at the same time?
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Here is an example: y = (x + 2)² + 5 (-2|5)
cos^2(x) / sin^2(x) = 1/tan^2(x) and cos(x)/sin(x) = 1/tan(x) ???
… The zero points must not change (and do not do it), otherwise the division by 2 would not be allowed. Or otherwise:
If pq formula and abc formula (aka: midnight formula) do not deliver the same result for zero points, then something went wrong in one of the two invoices.
have you been writing off?
2x^2-x-3
x2 – 0.5x – 1.5 = 0
you have divided 2
you take x2 – 0.5x – 1.5 times 4 you have the same zeros because you have to split by 4