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Delta45
1 month ago

A polynomial over a body disintegrates into linear factors in its algebraic conclusion. If the basic ring is zero divider-free, it follows that there are no more than # linear factors= Deg polynomial zeros. In general, a polynomial can have more zerotels, for example, polynomials via Mat(n) or C(R), the quadratic dies via C/continuous function via R.

Mathmaninoff, UserMod Light

If a zero x_0 is present, the linear factor (x−x_0) can be split off with a polynomial division, whereby the degree of the polynomial is reduced by one. This can only be done as often as the degree of the original polynomial was.

Rammstein53
1 month ago

Suppose a polynomial has n reelle zeros a1 . ., wherein individual zeros ak can be identical (multiple zero). The polynomial can then be represented as follows:

f(x) = b*(x – a1)*(x – a2)* … * (x – an)

When multiplying the n clamps, the highest potency is obtained to b*x^n, i.e. the polynomial is then also of degree n.

Delta45
1 month ago
Reply to  Rammstein53

Only true about algebraic sealed bodies. For R, b is a product (x^2+|am^^2) and c .