Physics (vertical throw)?

Could someone explain this to me, I'm stuck on the question.

Thank you very much 🙂

F 546: Sebastian stands on the winner's podium after winning a car race and removes the cork from a champagne bottle, which then shoots vertically upward at an initial speed of 8.50 m/s. The cork eventually lands on the ground in front of the podium, 2 m lower than where it started. Calculate without air resistance:

  1. How many meters does the cork rise?
  2. How long does it take to reach the highest point of its flight?

3 At what speed does he hit

when on the ground?

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Spikeman197
2 years ago

I would only expect 2) (t=v/g) then 1) (h=1⁄2gt2).

Then you just drop it 2 m deeper t=(2h/g)^1⁄2 and from time you get the speed (v=gt).

With the ‘passenger’ Formulas are also available directly to the results…

Spikeman197
2 years ago
Reply to  xrealxmxchelle

well, just drop out of 5,68 m…2 m deeper…

guteantwort626
2 years ago
  1. You need to calculate when the cork no longer rises, but is at its highest point. Consider what’s at the highest point, so you’ll get to the solution
  2. can be calculated with 1
  3. With the solution from 1 you can take a free fall from the highest point and calculate this
Kaenguruh
2 years ago

1. After the energy conservation rate, he has the same speed as when he returns from above at each point as when he rises at this point. It therefore has v=8.50 m/s at the level of the firing. So we can re-form the question: from what height does it have to fall so that it has this speed?

Formula: v = √(2 g h). With v = 8.50 m/s. Dissolve after h!

Two. From the same considerations: formula: s = g/2 t2. With s = h from the previous task. Dissolve after t!

3. From height h, it just goes 2m further than h from 1st task. Formulas: v = √(2g (h+2)) and (h+2) = g/2 t2, dissolve after t!

small precision; what I said about speed, of course, only applies to their amount (don’t be Velocity). The speed is a vector!

General Tip: According to my experience, many such tasks (at least about the idea) can be solved with the help of the energy conservation set. We did not need it here as an explicit formula, but implicitly about a mental approach.

pipipopo117
2 years ago
  1. The cork rises 8.50 m.
  2. The cork needs up to the highest point of its flight t = sqrt(2*2 / 9.8) = 0.45 s.
  3. The cork strikes the ground at speed v = -9.8 * t = -4,41 m/s.
guteantwort626
2 years ago
Reply to  pipipopo117

I don’t think it makes sense to write the solutions directly. The FS should do it yourself, GF is not a Mach-My homework platform!

Spikeman197
2 years ago
Reply to  guteantwort626

If the results are soo wrong, I always think that is intentionM

Spikeman197
2 years ago
Reply to  pipipopo117

All three results are completely wrong!

“Antwort of

2 minutes ago

  1. The cork rises 8.50 m.
  2. The cork needs up to the highest point of its flight t = sqrt(2*2 / 9.8) = 0.45 s.
  3. The cork strikes the ground at speed v = -9.8 * t = -4,41 m/s.

How I know: professional experience”

guteantwort626
2 years ago

All right, the criticism goes to the answer and not to your question. I think it’s good that you’re trying to do it yourself.

guteantwort626
2 years ago

Of course, there are certain accounts on this platform that upload their entire homework and expect them to be processed for them. They deserved that.

Spikeman197
2 years ago

I don’t think so. Your criticism is natl. legitimate…you can make it ‘better’ (like you), criticize (also like you), or you let it! That’s what Trolle!

guteantwort626
2 years ago

I didn’t even look at the results to be honest. Of course it would be funny