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Hamburger02
Hamburger02
1 year ago

First we calculate the acceleration:

from v = a * t follows:
a = v/t = 3000 m/s / 168 s = 17,86 m/s^2

Now we calculate the route:
s = a/2 * t^2 = 17,86/2 m/s^2 * (168 s)^2 = 252.040 m = 252 km

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Rassler38
Rassler38
1 year ago
Reply to  Hamburger02

The task is really stupid and extremely physical or not? A rocket has no temporally constant acceleration.

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Hamburger02
Hamburger02
1 year ago
Reply to  Rassler38

I haven’t been wondering about that for a long time. Of course, the acceleration increases and is almost 0 at the beginning, since the mass of the rocket changes dramatically and at the beginning of the thrust just enough to raise the rocket. In addition, it does not fly vertically into space, but pivots into a circular path.

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Rassler38
Rassler38
1 year ago

I’ll give my must again:

The solution of Hamburger02 is probably the one that was required here, but the task actually looks as if it had to be Rocket equation work (which would be more physically meaningful). Therefore, also the information in the first picture of the rocket.

The interesting thing about rockets is that their mass varies greatly during the flight and therefore the acceleration increases more and more. Therefore, to consider this movement as a “uniform acceleration”, I do not think it is appropriate. Therefore, a warning: Do not assume that you can always solve rocket problems with the formulas v=a*t and s=1/2at^2.

(Maybe I’ll see something too.)

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