"The length of the acceleration track was 7000 m.
After constant acceleration, the sled reached a speed of 2972 km/h. Calculate the duration of the journey and the acceleration of the rocket sled.
I don't understand this at all and I'm not sure what to do 🙁 Can someone help me? This is not homework, but practice for an exam
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Loading...if the distance is 30cm and the time is 2sec Thank you very much if someone can calculate it for me because I really can't get any further
Except throwing height, climbing time and throwing distance
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I'm currently preparing for my tenth-grade final exam. Can someone explain task 2 to me?
Should be easy, you have a distance of 7000m and a constant acceleration.
Probably you can take half of the speed to calculate that as the acceleration is constant.
You should probably normalize the units of distance and speed (7km).
So search for correct formula, enter values you know and then change the formula.
You need two formulas:
Now you put the second in the first and receive:
Here you have everything to the time t. After this, you dissolve. Then you enter t into the second formula and can calculate the acceleration a.
Supplement: convert v to m/s so that a is calculated in m/s2.
With a linear increase in speed, the path is calculated from s = v*t *0.5… will you continue?
v^2=2*a*s, s=1/2*a*t^2
Turn to a btw.t, set values.