Physik Formel!?
Guten Morgen ihr Lieben,
Ich bin 72 Jahre alt und bereite mich auf eine Prüfung vor, leider sind meine Physik Kenntnisse nicht mehr so gut wie früher.
Darum möchte ich euch bitten mir doch zu helfen.
Danke ihr Lieben.
Wünsche euch einen schönen Tag für heute trotz dem Wetter.
Now that this is at least the second question that needs to be used in the same formula, I will give you an overview of the physics formulas used in school as a basic prerequisite.
My teaching concepts and more you will find underhttps://www.dropbox.com/sh/x56zbd1s9h9s199/AACTraaBO6hPukv2PMkjFB-_a?dl=0
Tasks in mathematics and physics with solutions can be found under http://www.raschweb.de/
Explanations of physics can be found underhttps://www.leifiphysik.de/
The wire and the battery together have a resistance of 0.1 ohm. (the two are connected in series)
At 4 volts voltage, a current of 4 V / 0.1 ohm = 40 A is expected.
Hi TrixiePumi,
to calculate the current intensity II flowing through the copper wire in a short circuit, we can use the Ohm law, which is:
I=U/R
Here, U is the voltage and R is the total resistance. In this case, we combine the voltage of the battery and the total resistance.
The totality of the resistors is composed of the internal resistance of the battery and the resistance of the copper wire:
RTotal =Rinside and outsideRwire=0,04 Ω+0,06 Ω=0,10 Ω
Now we put the values in the formula for current strength:
I=U/Rtotal = 4Volt/0,10 Ω = 40 A
The current which flows in the accumulator battery in the event of a short circuit is thus 40 amperes.
Greeting, BigBee
Sounds very like ChatGPT and Co…