Good evening, is my completed task a) wrong? The static friction force Fhr and the weight force Fg balance each other out if the passenger shown here is pressed against the inner wall of the cylinder and does not slide down. Then only the centripetal force Fzp acts on the passenger shown here. However, the solution states that the passenger shown is subject to the force of gravity Fg, the force of static friction Fhr, and the force of the support surface. Is that correct? Important additional question: Is the support force here the same as the centripetal force Fzp, ie just a different name? Task: Solution to the task: My completed task a):

[Physics] Fairground physics: Rotor/carousel?

Bymaennlich2002 November 1, 2023February 27, 2025

Good evening,

is my completed task a) wrong?
The static friction force Fhr and the weight force Fg balance each other out if the passenger shown here is pressed against the inner wall of the cylinder and does not slide down. Then only the centripetal force Fzp acts on the passenger shown here.
However, the solution states that the passenger shown is subject to the force of gravity Fg, the force of static friction Fhr, and the force of the support surface. Is that correct?

Important additional question: Is the support force here the same as the centripetal force Fzp, ie just a different name?

Task:

Solution to the task:

My completed task a):

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Hamburger02

1 year ago

is my accomplished task a) wrong?

The approach is good, but misinterpreted. First of all, the dashed lines have no meaning, they should go away. And then the three acting forces are completely correctly drawn in the sketch: weight force Fg, static friction force Fhr and centripetal force Fzp.

The static friction force Fhr and the weight force Fg are the same when the depicted passenger is pressed against the inner wall of the cylinder and does not slide down.

That's correct. But only because they cancel each other because they have the same amount, but the opposite direction, they have not yet disappeared, but are still there.

Then only the centripetal force Fzp acts on the passenger shown.

Don't level, look up. Fzp is equal to the document force and generates the circular acceleration. Without the support (rear wall of the rotor), the guest would fly away straight away. Fzp forces him into the circular path.

However, it is found in the solution that the weight force Fg, the static friction force Fhr and the document force act on the passenger depicted. Is that right?

Yeah, that's right.

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maennlich2002

1 year ago

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