pH value of ammonia?
Calculate the pH value of an ammonia solution that has a mass concentration of 102.18 g/L.
Given M(NH3)= 17.03 g/mol ; Ks= 5.6 ×10^-10 (mol/L)^2
My solution is:
First I calculated the Pks value
-log(Ks)=PKs= 9.25 rounded
Pkb =14-9.25= 4.75
Then I calculated the substance concentration by calculating C=ß/ M and I got 6 mol/l
Now I have POH= 1/2(4.25-log(6)= 1.735
Now I have PH=14-POH which means 14-1.735 = 12.26
Did I calculate correctly? Because the solution simply says PH=12
If so, when can you simply round the pH value or if you get a pH value of 9.84, for example, can you then say 10
Thank you very much
pKb =14-9,25= 4,75
Then you keep going 4,25 of course.
Exactly, I wrote 4,25 in calculator although I knew 4,75 and written here
I’ll be there.
Thank you very much, that’s right I have an error.