Oxidation number of NO3-?
The solutions say that N has the oxidation number 5, but I would have said that it has the oxidation number 6, can someone explain to me why that is.
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Hi guys, can someone briefly explain to me what this is and what it is for
Hey, we're doing atom calculations in chemistry right now and I don't quite understand the following task: Determine the number of hydrogen atoms in 2.5 mol of water: How do I get the number of atoms from this information? Thank you very much for your answer/explanation.
because an unloaded NO3 does not exist! It is the NitratIon NO3(-) which makes it N(V). Since this is also the number of external electrons (see main groups No) is no longer possible!
If a peroxide would still be possible. But then it would be only N(IV), because O2 is only (-II) and not (-IV)!
Forgot the minus sign, but still don’t understand your answer
Each O in the nitrat is (thought) an O 2
Total one (1) charge remains.
“How much + does the N have to bring that out?”
6 ;
because
03: -2-2-2=-6
N: so that the sum equals zero must be N=+6, since -6+6=0
3*-2 (loading of O2) + x=1 (load of nitrate). rho again high
If the sum equals zero, it is unloaded. Nitrations are not unloaded, but simply negative.
It is not 0 loaded, but 1-