How to calculate the voltage of the following galvanic elements:
Copper and zinc with:
Standard potentials
Cu/Cu2+ = 0.35 V
Zn/Zn2+ = – 0.76 V
c(Cu2+)=c(Zn2+)= 0.5 mol/l
and
c(Cu2+) = 0.5 mol/lc(Zn2+) = 1 mol/l
Please provide detailed calculation method
(1 votes)
Loading...In math problems where I have to calculate the amount of substance, for example, the teacher tells me we should also do this ratio. For example, aluminum sulfate is a ratio of two to three. But I don't understand what that's for. So why do I have to calculate it? What's the point?
I have a question in my test that I can't find an answer to. The question is "Before regulating the flame size, the air supply must be closed. Explain this sequence." Does anyone know the correct answer to this question? Thanks in advance.
As far as I know, the OH concentration apparently increases when you add more base to a buffer system. But I don't really understand where the OH ions are supposed to come from.
Yesterday in chemistry class, a friend and I wondered whether J!zz is a homogeneous or heterogeneous mixture? 😂😂
What did I do wrong in c)? Shouldn't the oxygen decomposition pressure increase with increasing temperature?
Does anyone know the reaction equation for lactic acid and aluminum? And also the reaction equation from nitrogen to nitric acid?
I just don’t have enough time to count on it, but if there’s any more questions I should just report it then I’ll guess if I have more time. In principle, you have to make three calculations: twice set up the Nernst equation (one per half cell each) and then form the difference of the potentials resulting therefrom. This then corresponds to the cell voltage.
Mvg
Hello, yes I would be grateful if you could do that. I’m just talking about the result, but if you get out of something else than I would like to know why. That’s why with the three equations as you described it.
Show us your bill and we’ll tell you if it’s true.