Multiplicative inverse in modulo?
How do you do that?
e.g. find the multiplicative inverse of 3 in Z 7 .
Then that means the following
3 * x -1 = 1 mod 20
How do you get the right x?
How do you do that?
e.g. find the multiplicative inverse of 3 in Z 7 .
Then that means the following
3 * x -1 = 1 mod 20
How do you get the right x?
Hi. How do I calculate the two tasks? I have an approach for 4.2.1, but how do I calculate the equivalent reluctance? Unfortunately, I don't know how to get the value for x in 4.2.2. Can someone please calculate it for me? I drew the equivalent circuit diagram Here, the equivalent circuit doesn't change because…
Please provide exact solution Thanks in advance 🙂
So now I don't know which one is wrong. Lg
Hey, I'm taking a GFS (Equivalent Assessment of Student Achievement) in math this year, and my topic is the height theorem . This is my first time taking a GFS in math, and I'm a bit overwhelmed as to how to structure it all. In the GFS, I'm supposed to explain what the altitude theorem…
Hello everyone, I would like to calculate the missing point in b). Do I have to perform the following vector calculation for this? Line AB = Line BC? Then I get x= 8.5 Thanks for your feedback!
Hey, I'm unfortunately stuck on a problem right now, and I can't find a good online explanation that logically shows me how to arrive at the solution or the calculation method without skipping any steps. Maybe you can help 🙂 (18ax + 9x + 36a + 18) : (6a + 3)
If with Z7 the residual class ring is modulo 7, which contains the elements {0,1,2,3,4,5,6}. For the inverse I of 3:
3*I module 7 = 1
Solution I = 5, because 3*5 = 15 and 15 modulo 7 = 1
The solution is determined by sampling or by more or less complex algorithms. There is no simple formula for the solution.