Molar equivalents?
How do I calculate the molar equivalents in this example?
So from 1.099g MnO2 (M=86.94g/mol) and 0.671g cinnamyl alcohol (M=134.17g/mol)
(1 rating, 1 votes, rated)You need to be a registered member to rate this.
Loading...
MMn is quite a lot wrong and a lot crossed!
1. Do not include units in brackets! So it's called 'm in g' or 'm/g'.
Two. If I were to advance the relevant material properties as far as possible, for example the molar mass, but also the density!
3. The density of cinnamaldehyde is wrong! Organic liquids have a density of 0.9 g/ml if they are not exactly halogenated!
4. The amounts of substance are also incorrect, or have a vagueness. only the wrong unit. If necessary, fits mmol!
Five. Your molar equivalents are the mass ratio of the reactants. Theoretically, one would have to look at the reaction equation, but since organists are lazy and the 'help component' is usually cheap and used in excess, they usually expect a 1:1 ratio anyway (which is correct here). Thus, 95 mmol to 90 mmol is calculated here and comes to a 1.06:1 ratio (MnO2 in a slight excess)
I hope this is the first approach calculation you need to do!
I know corner brackets in this context, but vice versa: [n] = mol
(read: the unit of the amount of material is mol)
Unfortunately, this is rarely observed in chemistry…
[x]= "unit of x"
{x}="number value of x"
h=1.97 m…but you 'will' leave the unit…
=> h=1.97 m|
h/m=1.97
Ultimately, this is even a DIN standard!
https://de.wikipedia.org/wiki/unit characters
"Setting the unit character in square brackets, as it is written in some texts (eg " R [kΩ]), contrary to standards DIN 461 , DIN 1313 and EN ISO 80000-1."
Thank you for the detailed answer!
In the quantities of substances a write error has actually occurred! n(MnO2)=0.0126mol and n(cinnamalcohol)=0.0050mol. That is, in my example, the ratio would then be 12.6:5 in about 2.5:1.
Density should be correct because the cinnamon alcohol was present as a solution in chloroform.
That's worse! Then it is not a density, it is a concentration!
The next question is why 0.671 g of cinnamaldehyde (previously) were dissolved in 5 ml of chloroform. Probably these are just the reaction conditions. Nevertheless, you must have the cinnamaldehyde as well as 'determined'! Probably filled with a syringe or a pipette on a scale.
What are molar equivalents?
In the organic synthesis, the excess of a reactant is added. Theoretically the ratio is perhaps. 1:1, but practically 1.1:1 or 2:1 or even 10:1 are taken.
Oh, okay. But this is an empirical size? How do you calculate that?
Power the magnetic stirrer, I drink coffee for so long :-))
Yes, get it.
Finally, yes… in cooking regulations, this is usually stated or it is derived from the information. If one then varies (quantities, or components) one ortinates and then has to optimize (1.1:1 is cheaper than 2:1, but if necessary the yield is higher at 2:1, which is relevant for expensive components!)
I'll say…if you get BromReste: Do you want thiosulphate on it until it's colorless, or do you run 2 h to consume as little as possible?