MO orbital theory CO?
Good evening,
I'm studying chemistry and I have a question.
We're supposed to calculate the bond order of carbon monoxide, and I get 1, but it's actually a triple bond. Can anyone help me?
thanks in advance
I have a Casio fx CG 20 graphing calculator and want to set up a system of equations to solve these problems, but it's not working. What should I press? Does anyone have any knowledge of this? I don't know why it doesn't give me a function equation, and how am I even supposed to…
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Hello, I have solved some problems in my chemistry homework and would like to have them corrected before I hand them in. It would be very nice if someone could look over them. What goes from left to right in the PSE? My answer:Main and subgroups What goes from top to bottom in the PSE?…
The question may seem nonsensical at first glance, but if I have researched correctly, trees do not actually store CO2 (carbon dioxide). Because if you look at what a carbon dioxide molecule consists of, namely one carbon atom (C) and two oxygen atoms (O2), you will come to the conclusion that a tree can only…
What is the value of the red line: 10^2.6???
You also take off the non-binding electrons. You can’t. Binding order is binding electrons—antibinding electrons by 2. You don’t have any anti-bindings, but you don’t have any. Say the invoice is (6-0)/2 = 3.
Thank you. I was very different from videos and professors
Can you explain this to me for O2? Did you get out of your model BO=3, I murmured from Z=8 or Z>8 there is a new model without anti-binding electron pairs, right?:)
In the O2 you have 2 electrons in the binding σ orbital and 2 in the two binding π orbitals. One electron in each of the two anti-binding π orbitals is added.
Power (6 – 2)/2 = 2