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ProfFrink
10 months ago

It is alternately added and multiplied by an incremental operand

3 1 = 3

3 + 2 = 5

5! 3 = 15

15 + 4 = 19

19! 5 =95

95 +6 = 101

101! 7 = 707

retzi1
10 months ago

This is simply in the gap belonging to 101

It is always added and multiziplable. The number used is always greater by 1

First of all, then plus 2, times 3, plus 4, times 5, plus 6 and then 7

Willy1729
10 months ago

Hello,

101

Best regards,

Willy

lsp07
10 months ago

101

lg

ralphdieter
10 months ago

*1, +2, *3, +5, …

rr1957
10 months ago

the solution is 101.

the method is *1 … +2 … *3 … +4 … *5 … +6 …*7