Math fractions?
Justus has a bag of 40 candies. He wants to eat one-half of them every day. Calculate how many candies he eats per day and how long the bag will last.
Justus has a bag of 40 candies. He wants to eat one-half of them every day. Calculate how many candies he eats per day and how long the bag will last.
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Das was unterm Bruchstrich steht, wird mit der entsprechenden Zahl dividiert.
Also:
Lösungsvorschlag 1:
Also, gehen wir davon aus, er weiß, was Runden ist und wann genau man Ab und Aufrundet und wenn es weniger als 1 wären, würde er trotzdem 1 Bonbon essen, weil das Bonbon teilen will er nicht. Dann ist das Ergebnis wie folgt.
Also ist er am ersten Tag 8 Bonbons.
Folgende Auflistung sind jeweils die Tage.
Also hätte er am 15. Tag das letzte Bonbon gegessen.
Lösungsvorschlag 2:
Die 1/5 beziehen sich immer auf die 40 Bonbons und er isst jeden Tag immer 1/5 von diesen 40 Bonbons, somit würde er nach 5 Tagen keine Bonbons mehr haben. Warum? 5 * 8 = 40
Anyway, you have to count as the first 40:5 that would be 8,
So he eats first 8 a day.
So what he only has to count 32:5, etc.
Love
I suppose it’s linear.
40 – 8 = 32
32 – 8 = 24
24 – 8 = 16
16 – 8 = 8
8 = 0
Five days.
How do you get on the 8th? So I already know how you got on it, but the way of calculation is missing. 😉
40 * (1/5) = 40 / 5 = 8
or
100% / 5 = 20%
20% of 40 = 8
and
40* 0.2 = 8
Excuse me, Mr./Mrs. Teacher:P
I also thought – but given the level of the task, the linear computing path would be easier to explain.
We should ask Justus…
:
But the question is whether Justus thinks it as he says. He says yes
About 1/5. 1/5 of the 40 candies he had at first or 1/5 what he left after each day.
Since I know Justus, all the candies would eat on a day.
Ernst:40:5=1/5=Result:5…
That’s what I’d do.
I thought at the beginning, but now I understood them differently. So that after every day fewer candies are there.In the interception he has 40 and is 1/5 of them. Then he still has as example 34 of it he is again 1/5.Orbhabbich misunderstood?
32, not 34
I’ve been thinking, too, but that’s kind of not sensible, because on the 2nd day breaks get out and there’s no solution, because it’s converged against 0, but never 0…
Did I say yes, you have to count the result from 40 by 5 by 5 and the result of it again by 5, of which the result again by 5 and in the end simply count as many days it was.