ByJd637
Please help me with the following task.
I am in the upper elementary math class and the current chapter is called Angles Between Vectors.
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How do I solve the problem? A) Use points A, C and B and determine the function of the 2nd line (or the 3rd?!?!!?) using a system of linear equations. B) Determine the local maximum of this function and determine the distance to the blue line and the maximum.
Hello I might like to study medicine one day (I'll be graduating from high school next year). I'm also doing very well in almost all subjects, such as math, physics, chemistry, history, etc. But I have a hard time with languages. In German I only got 7 grade points (3-) In Latin I got 8…
I don't understand how you get the solution and the connection and why it is π/b now?
You don’t need vectors for this. You can lay a vertical cutting plane through the center of the base area and the tip – either along the diagonal or parallel to the sidelines of the base area. In the triangles formed and already present, you draw suitable heights and apply the phrase of the pythagoras several times. The angles can be determined by the definitions of sine, cosine and tangents in the right triangle.
If it should be vectors: The easiest thing is probably to start with location vectors. The origin of the coordinate system is placed either in the middle of the base or at a corner. Probably a corner is easier to calculate.
Calculate the coordinates of the corners of the base and the coordinates of the tip.
The vectors of the sides are the differences of the location vectors of the end points.
The angle is determined by
cos(phi) = a. · b) /a.|b)| )
(a. and b) are the vectors, phi the angle between them – when one assembles the “beginnings” of the vectors. At triangle angles, it is necessary to take care of where which vector goes. It is possible to calculate the outer angle and to convert it to the inner angle.)
1) Diagonal base (Pythagoras)
2) Side length triangle (Pythagoras)
3) Base angle triangle (cosine)
4) Top angle triangle (angle sum triangle)
The length of the four oblique sides is l. Then, according to Pythagoras:
(35.4/2)2 + 21.62 = l2
This follows l ~ 27.93 m
No vector calculation is required for the angle of a side surface. In the above rectangular triangle, the inner angle is:
l*sin(w) = 21.6
This follows:
sin(w) = 21.6/27.93
w = arcsin(21.6/27.93) ~ 50.66 °
If I understood correctly, you should share 35.4 by 2.
Then we have the first side of our triangle, so a. And the height 21.6 meters is our b.
Now you can choose the formula, a to square plus b to square = c to square.
According to my calculator, 35,4 is 1253,16 square, b is 466,56 square.
The two added yield 1719,72.
The root of 1719,72 is rounded 41,47
Hope I did everything right
So I calculated the length from the middle of a to the top. If you should calculate from the corner to the top just say it
I don’t think we can take the height as b, because the triangular side surfaces are not at 90° angles to the ground, so that the height of the Louvre does not correspond to the height of the triangular side surfaces. But thanks anyway!
Yeah, okay, I did what I can