Hello, I need help with tasks a and d. I've already done tasks B and C. We're supposed to use the sine and cosine theorems. I don't understand tasks A and D. Can someone please explain them to me?
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Loading...Signal words, my dears. Please tell me all the ones you know and that exist…I need support.
I wrote this paper today. Would anyone like to calculate it for me?
Can someone please help me with this task
I made a mistake somewhere. Probably somewhere near the top. Unfortunately, I can't find my mistake. I would really appreciate some help.
To a) The beginning is with the sine theorem
made.
In task d) it is
Addendum after comments (example to a):
I use the notation arcsin instead of sin -1 because I find the notation sin -1 prone to confusion with 1/sin, even though calculators label the key either sin -1 or asin . The phrase "sine to the power of -1" associated with this notation is also completely incorrect, since the superscript -1 refers to the inverse function of the sine, not any power of the sine.
With this variant you have to do something with arc sinus, which we haven't had yet or as I don't understand it exactly
Yes, you have to. Without knowing the inverse functions and covering them in class, there's no point in even mentioning the sine theorem. It would be useless. It could just be that you called it sin -1 instead of arcsin.
Thank you for your detailed answer. I understand now.
Please see my addendum in the answer – there you will find the example for task a).
So I just have to make the result that I get, 0.37 sine to the power of -1, then I get 21.7°, that's right then, or how
Oh, yes, we've done that before. But how exactly do I do it?
b/sin(beta) = a/sin(alpha)
Daraus berechnest du alpha, aus alpha und beta berechnest du
gamma und aus b/sin(beta) = c/sin (gamma) berechnest du c.
I actually tried that, but then I tried it, and it came up with an impossible angle value. So I googled it, and it said you have to do something with arc sine, but we hadn't discussed that in school.
What did you expect?
How do I figure that out? I'm no math pro.
Calculator set to degree measurement (DEG)?
You have to calculate the 0.36 with arcsin (INV SIN on the TR)
convert to degrees.
sin(34)÷25×16
So then it is transformed like this and then 0.36 comes out