Math experts, movement problems with 2 variables?
Hello ,
I'm currently studying for a math exam on systems of equations. However, I'm not making any progress on this task.
A hike is 39 km long. Two hikers set off at 9 and 10 a.m., respectively. They meet at 1 p.m. If they had set off at the same time at 10 a.m., traveling 0.5 km/h faster, they would still be 3 km apart at 1 p.m. Determine the speeds.
Thanks to everyone who wants to help me (PS. The first person to answer me will get the most helpful answer because I am pressed for time (but only if the person can figure out 6&5 km/h)
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You make a equation:
* v1 + 3 * v2 = 39
At the meeting point the first hiker was 4 hours traveling at speed v1, the second hiker was 3 hours traveling at speed v2. Together they travelled 39 km.
3 * (v1 + 0.5) + 3 * (v2 + 0.5) = 39 – 3
If both of you leave at 10 a.m., both of you are on the way. The speed is 0.5 km/h higher. Since they are 3km apart, they have laid 39km-3km = 36 km back together.
The second equation forms you to
* v1 + 1.5 + 3 * v2 +1.5 = 36
* v1 + 3 * v2`= 33
v1 + v2 = 11
Now you have a simple linear equation and can calculate v1 and v2.
Thank you.