Lichtgeschwindigkeit in den Maxwell-Gleichungen?

Hello ZuNiceFrage,

we only need 2 of the MAXWELL equations:

(M3) ∇×E› = −dB›⁄dt
(M4) ∇×B› = μ0∙j› + μ0∙dE›⁄dt = μ0∙j› + dE›⁄c2dt.

In vacuum, the current density j› = 0 is reduced, and there (M4) is reduced

(M4*) ∇×B› = dE›⁄c2dt.

E› is the electrical field strength, B› the magnetic flux density, μ0 is the magnetic field constant and ε0 is the electrical field constant. In addition,

(1) ∇:=(∂⁄4x ∂ ∂y ∂⁄4z)

the vector operator Nabla, who partially differentiates everything according to the coordinates behind it. The cross product stands for the differentiation taking place virtually “over cross”, namely in the form

(2) (∇×E›)_e= ∂E_y⁄4x – ∂E_x⁄8y.

This size is also called “rotation”; it “misses” the “ringelrum” parts of a field.