BySeran004
Two cars drive towards each other on a test track s = 150m. They start at exactly the same time, waiting for a starting signal.
Car A has an acceleration of a=3m/s^2 and car B has an acceleration of a=6m/s^2.
How long does it take after the starting signal until the two vehicles cross each other?
(1 votes)
Loading...The solution is moment D: DG × FGy + DA × FA = 0 But why isn't the horizontal force FGx taken into account? Is there a law for this? Or do you know of a PDF or website that contains the formula for technical mechanics, including for multi-part beams? Thank you in advance!
Hi guys, What is a waiting fare for a taxi?
I have a question about firecrackers that I bought. Does that mean the firecrackers are 135 dB loud at a distance of 15 meters? And what does the AI mean? ?
I have to solve task 3 b ) and unfortunately I can not get the value Can someone please help me with this would be very nice thank you in advance Best regards, xy
Unfortunately, I can't get any further here. Could someone help me? The trajectory of a stone is approximately described by the function h, where h(x) = -0.05x² + 0.1x + 1.5. Here, x is the horizontal distance of the stone from the launch point and h(x) is the height of the stone (each in meters)….
The equation for the distance covered is
s(t) = 1/2 a t
s1 + s2 = 150m
This allows t to be calculated.
Could you please tell me because I just can’t get on with this task.
I forgot two.
1/2 a1 t2 + 1/2 a2 t2 = 150
1/2 t2(a1 +a2) = 150
You should be able to resolve this after t,
fits!
Thanks for the solution I came to a time of t=5.77s. Is that right?
Why don’t you sign a suitable diagram and look at it graphically? :
Unfortunately, that doesn’t help me because I don’t know how to record it