Can anyone tell me the solution to this?
(1 votes)
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The minimum of the function K is requested.
A minimum is an extreme. These are found in which the zero points of the derivation are determined.
that is exactly the case when the counter is equal to 0.
The only logical solution x2 remains.
As a sufficient condition, the second derivation at the site is still valid to determine.
100 times w(3) as about 373 does not correspond to the true value of 173
chatgpt?
Then there would be root(3) = 3.73
I’m sorry.
100 * w(3) is correct
but the principle of your derivation is a mystery to me
It is also possible that the quotient rule is also taught in addition to the chain rule. I know that is not the case everywhere, which is why I carried out the derivation via the chain rule. In the first step, I rewritten the equation. This can be done because by sharing x is nothing else than multiplying with x^-1. Thereafter, it is derived according to the chain rule and (x+100)/x is expanded with x to reach a common denominator of both fractures and then simply further combined.
Here, as already mentioned in another answer, it would also have been possible first to perform the division by x and then to derive it.
well recognized. I need to correct
Thanks for your way
Here the errors
x2 generated
0 = 1x*x2 + 100*x2 – 15000!!! Each part of the right side needs the factor
.
Tip: The min is somewhere under 200
Thanks soup
Perfectly could you look again now have my final way out of all right?
bill itself must be correct, because 173 ( see here that is the derivation with zero point ) is
Where exactly is the problem to derive the function once and to search for the zero points of the derivation? So many can’t be…
I just want to compare if I did it right
old trick? Show that it is not that way and quickly write your solutions
Then write your solution in a clean copy with here.
I have corrected
I’ve been hanging
I did
calculate derivation and set = zero, then calculate x.
I would shorten by x for the first two summands
and rear is the derivation of 1/x standard: -1/x2.