Can someone help me with this zeroing procedure?
f(x)=x(x+2)(x²-3)
f(x)=0
I need the resolution in individual steps.
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The set of zero product provides:
Thus, there is no need to dissolve, because the function equation is already in the simplest form for the determination of zero points except for the last clamp. Only at the last clamp you have to
a little in the head.
Thank you. How do I get to the solution IN RESPONSIBLE?
Do you know the set of the zero product?
In Sophonisbe’s answer he is defined and evtkdocha has explained exactly what this means for your function.
If f(x). = 0 must be, according to the set from the zero product, x=0 or x+2=0 (resolve after x) or x^2 -3 = 0 (resolve after x).
What about x·(something) = 0 exactly when “x=0” or “something is equal to 0” do you not understand now? write to you “A product is always zero when one of the factors is zero.” and now you ask screaming for individual steps, if you do so from the functional term and the individual brackets direct read can. Sometimes you have the feeling questioner driving your scraper. Nice day…
Hello. No, as I said, I don’t know the set of zero product. I still thank you for your answer.
Excuse my ignorance! After more than 20 years, I’m going back to a school to make a training and never heard of it. That’s why I ask.
The set of zero product has already been mentioned here.
Which means one of the factors must be 0.
Either
x
x+2
or x2-3
x=0 is simple, there is already the solution.
For x+2=0, you can count on both sides -2 and come to x=-2
For x2-3=0 you add +3 on both sides and pull the root so you get to ± root(3)
Thank you.
Use the set from the zero product. A product is always zero when one of the factors is zero.
Thank you. And how does it work?
Very good. 🙂
(as described in my second sentence and extremely detailed in the answer of evtldocha.)
https://studyflix.de/mathematik/satz-vom-nullprodukt-3624