Kann mir jemand bitte diese Gleichung ordentlich lösen…?
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Physik Rechnung?
Hey wir mussten des im Unterricht rechnen. Das Problem ist, ich weiß absolut nicht mehr was dieser Rechen Weg war. Was ich für einen Rechenweg hatte. Ich hab das da drüber gerechnet, aber ich weiß, dass es richtig war, aber ich weiß nicht mehr hab, kann irgendjemand den Rechenweg reinschreiben
Mathe Analysis?
f(x)=15x^4 -30x^2 jede Tangente an Gf hat einen Schnittpunkt mit der y-Achse. Bestimmen Sie alle Werte, die die y-Koordinate dieser Schnittpunkte annehmen können. Kann mir jemand sage wie diese Aufgabe funktioniert? Vielen Dank
wie zeigt man , dass f konstant ist?
ich habe die Aufgabe ich dachte mir zuerst , dass eine Fallunterscheidung sinnvolle wäre für |a|>1 und |a|<1. Das Problem ist , dass ich nicht weiterkomme. Wenn ich |a|>1 habe , so bin ich näher an die null aber ich kann nicht wirklich was daraus folgern.
Kann mir jemand beim Faktorisieren helfen?
Faktorisiere so weit wie möglich: 4a^2 + ab + b^2 = 5c^2d^2 – 50c^2d + 125c^2 = Faktorisiere mit dem grössten gemeinsamen Faktor: 2a^2b + 4ab =
Wie berechne ich die Wahrscheinlichkeit?
Moin, lerne grad Mathe und weiß nicht wie man das berechnet. Deswegen folgende Frage zu dem Foto: welche Formeln muss ich nutzen und welches Video gibt’s dazu im Internet weil alles was ich im Internet finden kann ist Baumdiagramm, was ich aber dafür nach meiner Erkenntnis nicht nutzen kann.Danke im Voraus
Resolving orderly is difficult in this case. Even if you normalize this equation you still have an expression like this.
Here, however, it is worth calculating the square bracket
where, fortunately, two summands are subtracted. It remains:
Here the factor r to be shortened. r=0, however, is not a solution of the original equation because a “0 is provoked by 0” division there. I did not carry out a special limit check. By further calculation, the polynomial can be reduced to the following form:
This could be FataMorgana2010 has just closed off. It would lead to quite complicated root expressions. The numerical solution leads to two real solutions
x_01 = 1,9893
x_02 = 45,082
Is 45,082 the percentage?
You need to know what to do.
in the pension account r is a rate
What is the 4 for?
I don’t know. You have supplied an equation that uses the letter r as a variable. The question does not contain a reference to the ratio which should be expressed as a percentage. Maybe I would have
r_01=-1,9893
r_02=45,082
to write. These numbers solve the equation.
This is a quite legitimate method to imagine. Where what the mathematicians formulate as “presumption” can already be considered as a certainty in everyday use. Yes, I also got the 250,1 limit by an Excel test. He’s right and unequal to 45100. Therefore, r=0 is not a solution.
Not with the cardanic formula. This is for grade 3. Special with the solution formulas for equation 4. Here’s a wiki link.
https://de.wikipedia.org/wiki/Polynom_vierten_Grades#/media/file:Quartic_Formula.svg
Think about it. You can also calculate them exactly with a numerical method, which is arbitrary. If you need 20 decommissioning points, each numerical method also provides 20 exact decommissioning points. Instead, the solution formulas deliver a so-called exact result, almost infinitely accurate. But you get a coat of root expressions. If you want to make numbers from this, you have to start your computer again anyway. And he can only count the beautiful root expressions as exactly as his mantisse is long. Typically 10 descendants.
If it were the interest rate, r would be classic < 1 to have the classic interest rate of 1.x per 1 + r. Of course, interest rates of -198,93 and 4508,2 would also be conceivable, but untypical.
If I run r in Excel to 0, then I come 250,1; so would not be a solution. This, of course, is not a clean limit calculation, just a guess.
With the cardanic formula, you could calculate the solutions exactly?
I guess the formula comes from the financial mathematics – and was applied incorrectly. It would be better to stop the actual task.
I do not see anything else
It is multiplied by a gg with r^5 etc. Because of the -1 in the denominator it is possible to make nix
One could first substitute x=1+r (i.e. r=x-1). Then there is only x^4 -1 in the counter, which is equal (x2 +1)(x+1)(x-1) and then (x-1) can be shortened. Then it was brought to an equation with a maximum of x^4, which can be solved theoretically.
The problem is there should be an interest rate…
Check out the solution of ProfFink, it splits by r and lands at r high 4, which would be detachable again (cardanic formula).
Okay, I missed the answer from FataMorgana2010…