If someone could solve the problem e for me with calculation steps that would be great no AI can do that and unfortunately my secondary school teacher can't either but it's no use I have to be able to do that
(1 votes)
Loading...The question is as follows: The resistors R1, R2, and R3 are connected in series with U2 = 3x U1 and U3 = 4x U1. State the resistances R2 and R3 if R1 = 200 Ohms I hope someone can help me. Please explain!
I am looking for a website that should work like this: I take the number 37,000 Now I want to see how many balls or blocks = 37,000 So then 37,000 balls should appear there so that I can see how much that corresponds to
3 x 2 x 1/8 inch steel plate
Hello friends, can you help me with task c? in a) x1=1 and x2=-1 and at b) approximately 1.01 out
I bought a Casio HR-150CRE desktop calculator. First of all, I want it to work like a normal calculator. So if I enter 500-300-100 = then the result should be 100. However, when I do this with the desktop calculator, it comes out to -700. To subtract I have to enter as follows: 500 +…
5a)
b from g1
straight: y = gradient x + y-axis cutting point
y = m*x + b
4.5 = 3/4 * 4 + b
4.5 – 3 = b
y = 3/4 x + 3/2
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5e)
in two steps
-14
-3y = 3.75x – 7 – 14
-3y = 3.75x – 21
share by -3
y = -1.25x + 7
.
equation with g1 from 5a)
3/4 x + 3/2 = -1.25x + 7
3/4 x + 1.25 x = 7 – 3/2
3/4 x + 5/4 x = 5.5
8/4 x = 5.5
2x = 5.5
x = 2.75
and y?
3/4 * 2.75 + 3/2 =
3/4 * 9/4 + 6/4 =
27/16 + 6/4 =
27/16 + 24/16 =
51/16
D is ( 9/4 ///// 51/16 )
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PS For primary school, it’s too heavy. No wonder that so many have to leave without a conclusion
ja bayern stop nh we are so accustomed only you have to start somehow, but I am in the 10th grade so make my real school degree something in the art. I’m looking at thank you.
You probably know you well with mathe. The problem is I need to understand why I have to reckon exactly because the tasks are variable I have to recognize therefore why I have to count on these two points g2 and g3 if I only need one of the two
one straight line is 14-3y=3.75x-7, the other y=0.25x+4
For example, it is possible to insert the second at y into the first and then to dissolve after x, then the x coordinate of D. y is then inserted by inserting x into the simpler straight line equation
second inserted into first:14-3(0.25x+4)=3.75x-7
multiplicate, summarize and dissolve after x
Convert one of the equations to one variable and then to the other. Then determine the x value and finally insert it into one of the functions for the y value
The straight line is in a somewhat unusual form. You bring it to the normal form y= ax +b.
Then you think what it means is that two straight lines intersect. There, both the x value and the y value are the same.
Since you now have both straight lines in the beautiful shape, it is easy to put them over the y value equal and to calculate the appropriate x value.
I’m not so smart her can’t give me that kind of nay that I understand because how to learn this
I explained it hairy. What do you not understand about my explanation?
Try to read them exactly ..