Is this a reflection on the x-axis?
Hi, can you see a reflection on the x-axis in the image?
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No, this is a reflection on the axis y=7…
I don’t understand this, can you help me? I was taught that y= -f(x) causes a reflection on the X axis. The image is an exponential function, we say bsp. 5^x +7. -5^x + 7 would then be a splash on the x-axis? Why is it not a reflection?…
The mirrored version would be -5^x – 7. If you recreate -f(x), you have to set brackets y = – (5^x + 7). Because then the plus in the clamp becomes a minus when multiplying.
Because you need to mirror everything, also the +7 in -7 – then it is a reflection on the x-axis: so -5^x – 7 is a reflection of + 5^x + 7 on the x-axis…
No, because in this case the black function would then run under the x axis. Here you mirror approximately on the straight line y=7, which simultaneously represents a parallel displacement of the x-axis.
I don’t understand this, can you help me? I was taught that y= -f(x) causes a reflection on the X axis. The image is an exponential function, we say bsp. 5^x +7. -5^x + 7 would then be a splash on the x-axis? Why is it not a reflection?…
Right. And in your example is -f(x) = -(5^x +7) = -5^x – 7)
No, there’s no reflection on the x-axis.
I don’t understand this, can you help me? I was taught that y= -f(x) causes a reflection on the X axis. The image is an exponential function, we say bsp. 5^x +7. -5^x + 7 would then be a splash on the x-axis? Why is it not a reflection?
See comment on the answer of , When you calculate -f(x), it must be done so that it is also true and not only apply the minus sign to a part of f(x). -f(x) = (5^x +7) = – 5^x – 7