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jeanyfan
1 year ago

When setting the conditions: f'(2)=0, you always have an extreme point (or terrace point) at this point, so the slope is 0. Here, however, the slope is indicated by 2 so as to apply f'(2)=2. You probably confused.

FataMorgana2010
1 year ago

How do you get on f'(2) = 0?

There is that the function at point (2;0) has the slope 2, not the slope 0.

FataMorgana2010
1 year ago

Yeah.

ioasdbhjg
1 year ago

that makes no sense because the function is 0, so it would just be a line on the x axis

ioasdbhjg
1 year ago

have you done it? http://www.mathepower.com/steckbrieftas.php

entered. It shows that the function f(x)=0.25x^4+(-1.5x)^2+2 is.

In my opinion, if you enter everything there yourself, the way of calculation will be very well explained to you

Halbrecht
1 year ago

f'(2) = 2 . . . . .