Integral calculus rectangle through vertices?

The task is as follows

For every value of a > 0, a function fa is given by fa(x) = -ax^2 + a

The rectangle with vertices A(1I0), B(1Ia), C(-1Ia), and D(-1I0) is divided into two parts by the graph of fa. Calculate the ratio of the two areas to each other.

I am unsure about this and wanted to ask for an approach

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Vampirjaeger
1 year ago

The area of the rectangle is 2*a.

The two surfaces then behave like 4/3*a to (2-4/3)*a=2 to 1.