Integral calculus rectangle through vertices?
The task is as follows
For every value of a > 0, a function fa is given by fa(x) = -ax^2 + a
The rectangle with vertices A(1I0), B(1Ia), C(-1Ia), and D(-1I0) is divided into two parts by the graph of fa. Calculate the ratio of the two areas to each other.
I am unsure about this and wanted to ask for an approach
The area of the rectangle is 2*a.
The two surfaces then behave like 4/3*a to (2-4/3)*a=2 to 1.