Hello,
following problem:
I want to replace my ceiling light in the bathroom because it no longer works. I took out the fuse as you're supposed to do.
Problem: as soon as I touch the cables even though the fuse is switched off, the FI trips.
Why is this happening? Is it problematic?
Can I ignore it and just install the light?
Lg
(1 votes)
Loading...What is it and what is it good for? It's about all three things
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The fuse separates the external conductor from the network. You don’t have any more voltage on the external conductor. The nectral conductor and protective conductor are still connected. Since the neutral conductor is the return conductor of all circuits, and thus all are firmly connected to one another in the distribution, it also returns the return conductor current from other circuits. If this circuit is connected to the protective conductor in the switched-off circuit, then the return current flows from other circuits via the neutral conductor to the protective conductor and the RCD measures an error current and accordingly triggers a… Since the RCD for a plurality of circuits simultaneously realizes protection, all circuits connected thereto are switched off.
So that’s normal, and that’s right.
Thanks for the detailed explanation they have helped me very much 💪💪💪
It’s not problematic, it’s just what it’s supposed to do.
I am not a professional sry haha 😂
But where’s the point? The fuse is already out, why is the FI flying out?
The FI triggers as soon as you connect the protective conductor to the outer conductor, i.e. the voltage-carrying conductor. This also happens when the fuse is out. If you want to prevent this, you can temporarily protect the protective conductor with insulating tape during assembly. It’s not necessary.
If the fuse is out, the outer conductor does not release RCD. This is the neutral conductor and protective conductor responsible…
But bad isn’t it?
Yeah, sorry. It’s been a while.
Yeah.