Inclined plane, static and sliding friction, how to determine?
Shouldn't 25° be used here for mH (coefficient of static friction) instead of mG (coefficient of sliding friction), since from 35° the coin starts to slide and at 25° the coin sticks?
Why does the decay measured in the counter tube (Geiger-Müller counter tube) not correspond to the activity of the preparation?
Hello, Why do you get an electric shock when you touch a high-voltage power line? The cables are insulated, so they should be safe, right? But if you touch a charging cable, nothing happens. Thanks in advance for answers! Best regards!
Until he's no longer there?
For example, I have the task "15. In a living room light, six identical lamps, each with 60 W, are connected in parallel to 230 V. The resistance of one lamp is 882 Ω. Calculate (a) the current in one lamp, (b) the total current, (c) the equivalent resistance at 230 V." And I'm not…
Hello, how do I complete task 2a? How do I change it?
Good day, Can someone please explain to me how we get these solutions in tasks a, b and c? best regards and thank you very much
Yeah, that’s right. In this case, the coin is not yet in motion at an angle of 25°, so only the static friction acts. The sliding friction occurs only when the coin begins to slide, i.e. at an angle of 35°.
The static friction force is therefore equal to the slope output force, multiplied by the static friction coefficient:
F_H = mg sin α = μ_H mg cos α
μ_H = tan α = tan 25° = 0.466
The sliding friction force, on the other hand, is equal to the slope output force, multiplied by the sliding friction coefficient:
F_G = mg sin α = μ_G mg cos α
μ_G = tan 35° = 0,70
The value of μ_H is therefore correct in the illustration.
in the solution it has been made differently, the angle interchanged.