If you were to attach a bicycle dynamo to a battery and charge it, would the dynamo still charge the battery if it was rotating very slowly?
Or would he need at least the speed needed to light up a bicycle lamp?
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Under certain conditions, this would work depending on the design of the bicycle dynamo.
– In the provision of a charging voltage, it must be a direct voltage which, if necessary, can also be achieved via a rectifier.
– The charging voltage of the battery used must necessarily be below the rated output voltage of the dynamo; for a Li-ion / Li-Po cell, it would be sufficient because it would have a charging voltage of ~4.2 volts. In the case of Ni-CD and Ni-MH, it would be close to 4 cells in series, with PB only for two cells in series.
– Depending on the technology of the batteries used, a corresponding charger must be interposed, because during charging, minimum and maximum voltage must be stabilized in a certain range. In the case of undervoltage, the charging process is automatically interrupted (otherwise, the battery would be discharged again), and in the case of maximum voltage it is also necessary to be re-regulated until capped to protect against overload and thermal overload of the battery.
Since the rated power values of a normal cycle dynamo with 6 V/0.5 A (3 Watt) are quite manageable, a sensitive dimensioning of the battery capacity is also set to a rather low limit.
Depending on the design, the dynamo must, however, achieve a certain minimum speed in that it could effectively supply the necessary charging voltages for the respective battery technologies in the AC voltage part.
To do this, you need a corresponding circuit, you just can't clamp.
But if you have a responsive circuit, rectifier, charger, clear.
Even if the battery has more charge than it is, does it charge? If a device has to store energy first in order to be able to charge a battery with a higher charge, my next question would be how long is the energy stored in the device until it is converted to higher than battery charge?
Whether it depends not on the charge, but with the voltage.
But you can increase the voltage through a boost converter, or with AC voltage also by a transformer.
Where the stop should not be too high, the charger comes into play.
Yeah, you're 10.
AEM30940, the chip can start at 0.38V, after a few seconds it then runs permanently with voltages down to 0.03V. He'll give you that 3-4V. Works with AC voltage and DC voltage https://www.tekmodul.de/product/aem30940-energy-harvesting-powermanagement-ic/
If you want to get even higher voltages, you can enjoy a taser module from ebay https://www.ebay.com/itm/383901962093
Then you land at a few tens of thousands of volts(400kv would I doubt).
Is such equipment available for less than 100 euros?
Yeah.
You can also create over 1,000 volts only with fluffy socks on carpet no problem.
So you can take 0.1 volts to 777 volts with certain equipment?
Dynamo – AC voltage. The battery is not charged, but is killed.
Dynamo, rectifier – the battery is charged if its volt is below the generated volt of the dynamo. Many batteries have to be monitored and regulated during charging, otherwise they will break. Lithium something even with fire show. Lead acid batteries tend to stand out. But you shouldn't overdo it anyway.
Turn the dynamo slowly and its generated volts come under the volts of the battery, then lick more.
Both videos could be helpful if you want to increase your volts.
https://m.youtube.com/watch?v=m99OLrG0Cks
https://m.youtube.com/watch?v=-qzrWOXW1Ho
A dynamo supplies power as soon as it turns. It is not possible to say whether this amount of electricity is significant.