I don't understand?

To all math pros, how do I solve this problem? Could you solve it and then take a photo of it and post it? I always get something different with the problems except for the first one which is scribbled in red. I understand that one but not the others.

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Halbrecht
1 year ago

no idea what you did in the third line

in I is that y=x+1 is ….so you can replace in II y with x+1
-2x + 3*(x+1) = 1

Harvey1102
1 year ago

What are you getting out and how did you expect it?

Then you can go to troubleshooting.

Harvey1102
1 year ago
Reply to  Cutegirl13435

So the basic principle is that you use the first equation in the second.

Example for b)

You set x+1 for y in the second equation

You will then receive -2x + 3*(x+1)=2

Now you release the clamp and reckon everything with x and everything without.

After that, you change the x on one side of the = and the rest on the other side.

If you then get x=? out, you can insert it into the first equation and get y

How to do it with c) and d) in the same principle

Harvey1102
1 year ago

I’ll write it differently, maybe it’ll be more obvious:

II) -2*x + 3*y = 2

-2*x + 3* (x+1) = 2

Now the error comes in your equation, because you’ve been counting 3*1, but not 3*x.

It should mean:

-2*x + 3*x + 3*1 = 2

You can also write

-2*x + 3*x + 3*1 = 2

Now everything with x on one side and the rest on the other from = and then it should fit