Huh? Why is the voltage drop across a component X of a mesh supposedly the sum of the voltage drops across all other components within the mesh?
I would have thought that the sum of the stresses in a mesh is equal to the sum of the stresses caused by the components contained in that mesh, so the sum of the stresses in a closed mesh is zero. However, the following was checked in the discussion of the mock exam.
"The voltage drop across a component X of a mesh is the sum of the voltage drops across all other components within the mesh."
What does the voltage drop on a particular component have to do with it?
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The sum of the voltage of a mesh is zero. If you record this one by one and bring a single element to the other side of the equation mathematically correct, then there is exactly the statement that you are questioning.
So: Simply “make”, observe, understand, vary….
Yes, but the mesh rule says that the sum of the voltage drops in a closed loop must be zero if you go around the loop counterclockwise. This is about the total amount of tensions in the loop, not a single component X, or?
So all components X together have added the voltage drop 0.
Sum V_i = 0.
Yeah, that’s it. Now you bring a single element to the other side in this equation. You’ll get it.
The limitation with “on the left” or “on the right” forgets very quickly – that’s Bockmist. It is important not to make any sign errors in the voltage arrows. So first apply voltage arrows, then add.
Good luck!