Hi
Unfortunately, I don't quite understand how to solve number 6 on the worksheet. If someone could explain it to me, that would be very helpful 🙂
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Hey! I actually understand the problem, but I'm making a logical error somewhere. It would be great if someone could help me out. I'm not entirely sure what I did wrong; I've included my "calculation" below the picture. Thanks in advance 🙂
You can?
6b)
derive
f'(x) = x2 – 2x
0
0 = x2 – 2x = x*(x-2)
Extrema at x = 0 and x = +2
.
redirect
f”'(x) = 2x-2
f”'(0) = 2*0 – 2 = -2
-2 < 0, therefore Hpoint
.
.
.
(a)
f'(x) = 2x -2
f”'(x) = 2
Therefore, f”'(x) is always greater than zero, since only Tpoint is possible
Thank you