How do I solve this problem?
I didn't give any side length
I didn't give any side length
How do I partially square this?
There are 30 and 24 children in classes 5a and 5b, respectively. Of these, 12 and 10 sing in the choir. In which class is the proportion of choir participants higher? BTW it's about the topic of fractions. I would be happy to receive an answer.
Hey guys, I don't know why, but I'm really into chemistry right now, but the problem is that I hardly learn anything at school because the lessons are so short and the teacher doesn't explain much. When I search the internet for simple chemistry, I can't find anything and I don't want to look in…
In ethene C2H4, the two carbon atoms are linked by a double bond. Determine the energy eigenvalues and eigenfunctions of ethene using the Hückel approximation. f) Sketch the eigenvectors using pz orbitals.
Good day, I'm currently trying to solve a chemistry problem using the given solutions and I came across this: However, I don't understand how the 10^-7.2 was converted to 6.3×10^-8. Can someone maybe help me with this? Best regards and thank you in advance
Is my coordinate equation correct? There are many possible ones 🙂
Task 8
—
Root (5,42 + 32) = 6,177378
—
6,177378 * SIN(47,7) = 4,568981
—
x = 4,568981 * COS(35,4) = 3,724303
x is 3,7243 cm
Given:
Solution with the cosine set:
The cosine set is:
x2 = a2 + b2 – 2 times a times b times cos(γ)
1. Use values:
x2 = 5,42 + 3,02 – 2 times 5,4 times 3,0 times cos(96,9°)
x2 = 29,16 + 9,00 – 32,4 times cos(96,9°)
Two. calculate cosine value:
cos(96,9°) ≅ -0,127
x2 = 29,16 + 9,00 – 32,4 times (-0,127)
x2 = 38,16 + 4,12
x2 = 42,28
3. Pull root:
x = root of 42,28
x ≅ 6.5 cm
Answer:
The searched route x isexact root of 42,28 cmorrounded approx. 6.5 cm.
only Pyth in triangle with 5.4 and 3.0
then in DrEck with 47.7 Sinus
then in the DrEck with x Cosinus
You have three rectangular triangles. I think of the SATZ DES PYTHAGORAS, and when I see some angle, I think SINus, COSinus &TANgens
Try it with it
You have triangles, and you have the phrase of Pythagoras.
My pension
But without angle functions, this is nothing 🙂
They were already included in the triangles. That when reading the task, one does not ask why the values are clearly stated…
The angles are specified, not the functions to be used 😉