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JenerDerBleibt
1 year ago

It’s quite easy to think about.

1. As a halogen, Iod has the highest electronegativity here, it gets a desired electron and has the OZ-1. Hg usually occurs in the oxidation stage +2. Accordingly, [HgI4] has a charge of -2. Finally, it follows that the copper must be Cu+ to arrive nicely on a charge of 0.

Two. Works similar to above. The SO4 is the sulfate anion and, as is known, carries a charge of -2. Thus, the complex in brackets must have a total charge of +2. Since H2O itself has no charge, the copper must carry it. This is a Cu2+ ion.