Bytobi2247
Hello,
Can someone explain to me how I can determine the radius of convergence of the following series:
Normally, in a power series, I would look at the part that is multiplied by x individually and apply the root criterion, for example, but that's not really possible here.
The solution states r = 1.
Does anyone know how to get r = 1?
(1 votes)
Loading...Good evening, I was wondering how to solve this system of equations. I was pretty confused. I took a problem from an online book, and I can't solve it.😅 I hope you can help me. Thanks in advance. Solve the system of equations. 1. 2x+3y=9 2. -3x+3y=-1
I read Friedrich Engels' speech at Karl Marx's funeral, and there he claims the following: "But in every single field that Marx subjected to investigation—and there were very many of these fields, and none of them did he touch upon merely fleetingly—in each one, even in mathematics, he made independent discoveries." What discoveries did Karl…
What does this number mean?
Hello, I have the following expression and according to the task I am supposed to express it as x = a/b, how do I do that? (that should be an a and a b) I am very grateful for any support
How do I draw the diagrams here?
First question: Are there other symmetries besides axial symmetry, point symmetry, rotational symmetry, translational symmetry and scale symmetry? Second question: Does anyone know of everyday examples of translational symmetry and scale symmetry? When I read through the definitions, I can't really imagine what they mean.
Compared to…
… with the geometrical row…
… so you can see that it is a geometric series with q = x2.
A geometric row converges exactly when |q| < 1. In the specific case, one obtains as a convergence condition |x2| < 1...
Accordingly, the series has the convergence radius 1, since the series for |x| < r with r = 1 converged.
===========
Alternatively, you can also use the formula of Cauchy-Hadamard.
It’s…
Then…
This sequence n-ten roots of |on| obviously has the two grading points 1 and 0, where 1 is the larger grading point. That’s right.
For the convergence radius of the row, the formula of Cauchy-Hadamard…
A large series is obtained by forming x^(2n)=(x^2)^n. For this purpose, the convergence radius should be recognized, namely |x^2| < 1, i.e. |x| < 1. For the edge cases, the sequence is not a zero sequence, so the row diverges.