How did you come up with this drawing?
At the origin of the coordinate system, an exciter oscillates with y(0;t) = 8cm * sin(pi * t * s^-1).
Draw the wave for the times t1 = 2s, t2 = 3s, t3 = 4.5s and t4 = 7.5s in a common coordinate system.
This drawing was given in the solutions:
How do I get this? What values do I need to enter into the function?
You didn’t say anything about the wave’s spread. There is something missing… at least feed t=0 you should know the course y(x,0).
True, the exciter generates a transversal wave which spreads with c=0.2 m/s.
Other
and what is the equation:
y(x,t) = A*sin(wt – w*x/c)
You got something?
And you have c=0,2
Now you know everything and can draw it
0?
y(30,t) = 8*sin(π*t – π*30/0.2) = …?
Okay, thanks. Another task is to formulate the location-time functions for the vibrations at the points x1 =30 cm; x2 =80 cm and x3 =100 cm. In the solutions stand for x1 instead of sin then cos, for x2 remains sine and for x3 minus sine. How to explain this?
you just have the four functions
y(x,t) = 8*sin(π*t – π*x/0.2) where you use the four times for t and then against x plottest. Then you will get exactly to the specified solution sketch.
Yes, however, makes no sense, has now taken the general wave equation and then the right one came out, that is -8 for x=10 and 0 for x=20 and 8 for x=30 etc.
but only for t=2 and t=3
can your TR plotting?
Turned to the wheel, then there came 0 out
8*sin (pi*2 – pi*x/0.2) =0
What are you thinking?
Now entered my calculator f(x) = 8*sin (pi* 2 – pi*x/0.2). Then there are false values such as -3,903 for x=10 or 6,3147 for x=20.
🙂
So I should draw four functions
I want you to write x as a variable. In the solution above, x is also not given. You draw a function as a function of x. If I tell you to draw the function y=x2 you don’t say “what is the x?”
For t=2:
y(x,2) = 8*sin(π*2 – π*x/0.2)
For t=3:
y(x,3) = 8*sin(π*3 – π*x/0.2)
etc.
I honestly don’t understand what’s unclear about it.
No, but x is not given. When I calculate x by the formula t times c, I come to 40cm for t1 = 2s. If I put this in your formula from above, I get about 8 cm out, which can’t be right because the elongation at 40cm is equal to 0. So I now take the general wave equation y = ymax * sin (2pi (t/T – x/Lambda) I come to this 0, but then for t2 = 3s also 0 comes out, which cannot be again.
Do you even know what this is all about? I slowly doubt that… x is the coordinate of the location, t is the coordinate of the time. For t=2, 3, … you shall draw the spatial behavior, i.e. y(x,t)
If you’ve been dealing with waves for three days and now ask what the x is, this is very irritating 🙂
I don’t know what x is