How can you roughly calculate this in your head?
Hello,
How can you roughly calculate -e^-1 in your head? Is there a trick or how would you do it?
Hello,
How can you roughly calculate -e^-1 in your head? Is there a trick or how would you do it?
In b) I don't understand how to calculate a fair bet for two games if the higher of the two amounts is to be paid out… can someone just give me an idea?
Hello, my dears, Is anyone fit enough to solve this task or provide assistance? Thank you Greetings Alex
Hello, normally an ONB is not a problem for me, but here I am confused. For the ONB, I take e1(?) as the first vector and then continue with the eigenvectors? I've determined the eigenvalues: x=4, x=2, x=3/2+-√5/2. The EVs aren't very pleasant. So my question is, where is my error in thinking? Thanks 🙂
I have a math test tomorrow, and I don't know how to draw the second image of a truncated pyramid, and I can't find anything on the board. Could someone please help me with this task? A pyramid is cut parallel to a 6 cm high square pyramid with a base area of 18 cm…
The example is below. How do you calculate FA and FB? Then you simply apply the cosine theorem.
I know that e^(-1) is about 37%, i.e. about 0.37. [I noticed this from electrical engineering… When a capacitor is discharged, the voltage has dropped to about 37% according to a τ.] Accordingly, -e^(-1) is approximately -0,37.
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Otherwise, I would also know that e ≅2.72 is ≅3 and could thus approximate…
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Otherwise, I would also know the series development of the exponential function…
This could be approximate…
… or something more accurate…
… or something more accurate…
… or something more accurate…
… or something more accurate…
… and so on. [While it would be quite difficult for me with further calculation after the step with -0,375 in the head.]
🙂 the trick is third? fourth class? Written parts. Only now in the head
but with 2.7 !
1 by 2.7
10 by 27 in the head should go
is 0
100 by 27 = 3
81, rest 19 , 190 by 27 = 7 ( 189 )
almost perfect 0.37 , but of course -0.37
so much memory every head has to hold
-e^(-1) = -1 / (e ^ 1) ≅ – 1 / 3 ≅ -0.33
The true value is about -0,37
I can only e^0 in my head
But ne in my head is hard. My trick would be memorable..