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[Physics] Calculate the value of the resistor?
Good evening, I still need a little help understanding the following task. I'm really looking forward to your detailed answers. πββοΈ What is the value of R if log_10 (U1/U2) = 1 in the circuit shown? Where is the voltage source here? Since lg(U1/U2) = 1, U1/U2 must be 10, since 10^1 = 10, right?…
Well, in the famous formula E=m*c2 m stands for mass, not for matter.
For matter, i.e. the Quarks and Leptons, conservation rates apply. At least these days, in the first fractions of the second after the Big Bang, they may have been used by other natural persons who no longer have an effect today.
In any case, with all the energy of the world, it is not possible to produce a single electron, but only to convert a neutrino into an electron, parallel to it a down square into an up square. This is now more the Feynman style, one could also speak of the production of an electron and an anti-neutrinos. But this does not change the number of leptons, which remains zero because it is -1 for antiparticles.
It is also possible to produce particle-antiparticle pairs, electron+ositron or proton+ antiprotron, but the particle number does not change. So just create matter without antimatter, it’s forbidden. There are theories (or hypotheses) to a supersymmetry, after which protons can decompose into positrons and which then simply destroy themselves with an electron, but the m.E. are not ripe.
Energy can convert into matter and matter can convert into energy, according to the known formula of Albert Einstein E=mc^2, where “E” represents the energy, “m” the mass of matter and “c” the speed of light. This formula states that a small amount of mass is equal to an enormous amount of energy. The transformation of matter into energy takes place in many processes in the universe, such as, for example, in nuclear fusion into stars, in which light atomic nuclei merge into heavier atomic nuclei and release energy. The conversion of energy into matter can also be detected under certain conditions in laboratories on the earth by allowing high-energy particle beams to collide with one another and thereby producing matter for a short time particles which arise from the released energy.
Can you imagine it as if a black hole was created?
A SL is created with a certain mass ( Wolf Rayet stars 10-265 solar masses) in a specific area (black shield radius) so somewhere from 10+ solar masses.
Can a gamma Ray Burst of a Quasar’s then produce quasi matter? Because what is more violent than that does not concern energy density if I understood it correctly.
LG SRT2007
A GRB cannot produce matter. It is merely an enormous energy source that releases energy in the form of gamma radiation. The energy source of a GRB is not yet fully understood, but some theories suggest that it could be related to the formation of black holes or the fusion of stars in neutron stars.
Then I believe to have heard this, for example, a galaxy with an active SMSL (square) above and below the galactic pane a huge “halo” or, as you also call it, creates/forms…
LG SRT2007
It is possible that you remember another phenomenon in the universe instead of jets around Quasare. Quasare are super-mass-rich black holes that sit in the middle of galaxies and release enormous amounts of energy by sucking matter into them. The jets around Quasare are rays of plasma, which are ejected along the axis of rotation of the super-mass-rich black holes and contain enormous amounts of energy and matter.
Another phenomenon in the universe you may think is protostars. Protostars are star clouds, which form stars and contain huge amounts of hydrogen and helium gas. While the protostars form, jets of gas and dust can occur, which spread from the star cloud along the axis of rotation. There are also jets around neutron stars and other celestial bodies that work similar to Quasar-Jets, but the causes and processes behind these jets are not yet fully understood.
Didn’t one detect huge amounts of hydrogen gas or helium in the areas around the jets…or do I change what now?,…
LG SRT2007
Hello SRT2007,
for matter particles there are conservation rates. Therefore, a matter particle of pure energy (e.g. photons) can only be produced together with its antiparticle (Pairing), or radiate with it to photons (Couple destruction).
For pairing, a photon must be more than double Energy have the particle to produce it together with its antiparticle. If there are strong electromagnetic fields, such a reaction can occur.
This makes it just as soon as the energy density is high enough, matter arises.
Or when the energy density is low enough. In the beginning of the universe, as far as I think it is right, the energy density was too high as matter could have arisen, or do I remember wrong?
Almost right, at the beginning of the universe, according to the cosmological standard theory, the energy density was so high that matter could not have an inventory and turned into energy more quickly than energy could change into matter. One could also say that the universe was “too small” at the time to contain (in great style) matter, because matter does not need space, energy. This is now roughly wrong, but clearly more vivid than the equations of quantum physics.
So energy density has something to do with temperature…
The higher the temperature the faster the particles move?
Can you imagine it as if a black hole was created?
A SL is created with a certain mass ( Wolf Rayet stars 10-265 solar masses) in a specific area (black shield radius) so somewhere from 10+ solar masses.
Can a gamma Ray Burst of a Quasar’s then produce quasi matter? Because what is more violent than that does not concern energy density if I understood it correctly.
LG SRT2007
Like that.
spontaneous pairing, formation of heavier elements than iron.
E = mc^2
,…was clear…Einstein formula
I just don’t understand.
LG SRT2007
Look, this is basically quite simple, each matter particle has a certain mass. A proton, for example 1,67261898*10^(-27) kg. According to the monolithic formula E=mc2 this makes an energy of rounded 1,51*10^(-10) Ws.
The energy of a light quantum (=photon) is from its wavelength or Frequency dependent.
E=hf = 6,626 10^(-34)Ws2. This can be changed to f and becomes too
f= E / {6,626 10^(-34)} Hz
For the mass of a proton, a photon having a frequency of 2.27*10^(23) Hz or, in other words, a wavelength of 0.000132 nm (visible light has, depending on the color, 400-700 nm, gamma radiation approximately 0.001 nm)
Since a proton has an electrical charge, which can not arise “from nothing”, a particle and a matching anti-particle with the opposite charge must always occur. Thus, it takes two photons of the specified energy that come “sufficiently close” so that spontaneously a proton and an anti-proton are formed. After they have arisen, they draw on each other because of the different electrical charge and as soon as they “contact” they convert into energy again (Materie-Antimerie reaction). However, if the photons had a little more energy, the resulting particles are accelerated and move away from each other so that they have a certain probability to survive.
This probably doesn’t understand many π Me included. This simply means that mass energy IS. But I’m not a physicist. You can take 100 seconds of physics videos on YouTube. Good luck!
Jaaπ
Yes the channel is horny and subscribed by me π Have already seen all the videos and look forward to a new one,…even if it lasts longer between times until a new one appears…
LG SRT2007