How are the electrons filled after the N-shell? Is there a rule for this? For example, there is an atom where the 5th shell has 20 electrons, then 8, then 2. The 5th shell has a maximum of 50 electrons, but why isn't it filled?
(2 votes)
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Moin,
you can look at the Madelung scheme for the occupation of orbitals. For better understanding, you should have looked at the basics of the orbital model beforehand.
And clearly there are rules for the occupation,
And despite these rules, there are sometimes exceptions that are (at least of me) unexplainable…
I’m also right to have fun dealing with the model ideas about nuclear construction.
Keep going!
If you still have questions about the orbital model or about the occupation after the Madelung scheme, just post it…
LG from the Waterkant
The simple formula for the maximum number N=2n^2 of the electrons per shell does not take into account the interaction between the electrons. Nothing’s as simple as it looks.
You can forget the shell model. this is useless and has even been deleted from the curriculum. What is true is the orbital model – you can work with it.
We’re still using the shell model. But we don’t do anything yet in class where you can’t use the shell model anymore. I just want to learn something from my own, because I am very interested. I usually wanted to try to scream all possible molecules with a connection and that with the data from the period system. Don’t ask me why, anyway, it’s fun. I then wanted to find out how much valence electrons have an atom to know how the atoms can connect.
The N-shell can record up to 32 electrons.
The O-shell would theoretically be able to record up to 50 electrons, but there are no known elements that fill this shell:
6S: 2 electrons
5f: 14 electrons
6p.: 6 electrons
6d: 10 electrons
5g: 18 electrons (theoretical)
With the P-shell it went even further in the sequence, but in practice it is not relevant for the known elements.
mash
PS: note the comment from