Can someone please explain the problems to me or show me the calculations? I can't find an explanation anywhere. How do I know when the integral is 0, i.e., when is it closed and colon-free?
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T = z(t) = e^(it) for 0 <= t <= 2π
Thus, dz = z'(t)dt = i*e^(it)dt
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With the integration interval [0, 2π] from the second integral (single is a catastrophe here). This results
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Be now z=z conjugated with the integration interval [0, 2π] from the second integral:
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This applies to:
This approach can be used to solve the tasks.
Thank you very well explained! Suppose I would now have a circular disc with radius 3 and calculate the integral of root z over the edge. That would be integral 0 to 2pi sqrt(3e^it) * 3ie^ir dr or?
The Integrale in my answer integrate a circular rim with radius 1. In order to integrate over the entire circular area, a further integral must take into account the interval for the radius.