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How do you arrive at the approx. 13 watt losses in an old T8 conventional fluorescent lamp at the ballast? Has anyone measured the current and voltage?

Byhubertheiner604

When I asked Osram, they said the current was 670mA and the effective voltage at the fluorescent lamp was 110V. But then the ballast would have to be 120V. Very stupid question: When measuring the fluorescent lamp, do you also measure the ballast? P = U x I = 110V x 0.67A = 73.7W That…

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Transistor3055
Transistor3055
11 months ago

I’ll help you with the jumps, but I don’t give you the full result. You should be able to understand it yourself.

My 3 tips are:

  • It’s a resistance bridge.
  • A resistance bridge consists of 2 (here) unloaded Voltage dividers.
  • Mesh rule: The sum of all voltages a mesh is 0V.

Explanation on the 3 topics:

https://www.elektronik-kompendium.de/sites/slt/0306151.htm

https://www.elektronik-kompendium.de/sites/slt/0201111.htm

https://www.elektronik-kompendium.de/sites/grd/0608011.htm

Alternative:

You can also calculate the voltage at each resistor with the ohmic law U=R*I by first calculating the current in both branches (it is 2 series connection of 2 resistors). And then U=R*I used per resistance.

https://www.elektronik-kompendium.de/sites/grd/0201113.htm

Good luck!

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